Answer:
3.90 sq cm
Step-by-step explanation:
[tex]A_{equilateral\: \triangle} = \frac{ \sqrt{3} }{4} \times {(side)}^{2} \\ \\ = \frac{ \sqrt{3} }{4} \times {(3)}^{2} \\ \\ = \frac{9 \sqrt{3} }{4} \\ \\ = 3.89711432 \: {cm}^{2} \\ \\ \approx \: 3.90 \: {cm}^{2} [/tex]
