jculver27 jculver27
  • 12-11-2016
  • Mathematics
contestada

what is the equation in point slope form of the line passing through (0,5) and (-2,11)

Respuesta :

Pitymys Pitymys
  • 09-08-2018

The equation of the line passing through [tex] (x_1,y_1) [/tex] and [tex] (x_2,y_2) [/tex] is

[tex] \frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1} [/tex]. Here

[tex] \frac{y_2-y_1}{x_2-x_1} [/tex] is the slope of the line.

Substituting numerical values, the equation of the line is

[tex] \frac{x-0}{y-5} =\frac{-2-0}{11-5} \\
\frac{x}{y-5} =-\frac{1}{3} \\
3x=5-y\\
3x+y=5 [/tex]

The equation of the line is [tex] 3x+y=5 [/tex]

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