Hello!
[tex] \sqrt{ {9} {x}^{8} {y}^{2} } = 3{x}^{4}{y}[/tex]
Will be. :)
1/2 = Square root
Then.. :)
[tex] \sqrt{3 {x}^{4}y } = \sqrt{3y} {x}^{2} [/tex]
Or,
[tex]( {3y})^{ \frac{1}{2} } {x}^{2} [/tex]
So, Answer : D
Have a nice day!
