tariqtalha94
tariqtalha94 tariqtalha94
  • 15-04-2018
  • Physics
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please tell the answer with full explanation

please tell the answer with full explanation class=

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AL2006
AL2006 AL2006
  • 15-04-2018

Potential energy to lift the load = (40 N) x (0.5 m) = 20 joules.

Usable power from the motor = (0.2) of (40 W) = 8 W = 8 joules per sec.

-- You need 20 joules to do the job.

-- You're getting 8 joules per sec from the motor.

-- At that rate, it'll take (20/8) = 2.5 sec to do the job.   (choice-B)
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