There are 36 different combos for the two: 6 possibilities for the first die times 6 for the second.
Out of those 36, 10 have a sum of 9 or higher:
3&6, 4&6, 4&5, 5&4, 5&5, 5&6, 6&3, 6&4, 6&5, 6&6
The probability is 10/36, which reduced is 5/18.
As a decimal it is 0.2[tex]\overline{7}
[/tex] and as a percent it is 27.[tex]\overline{7}
[/tex]%.
Hope this helps!
