[volume of a cylindrical paint can 1]=[area of the base]*h so [area of the base]*h=1 gallon
if the height is doubled [volume of a cylindrical paint can 2]=[area of the base]*(2*h) [volume of a cylindrical paint can 2]=2*{[area of the base]*h)} [volume of a cylindrical paint can 2]=2*[volume of a cylindrical paint can 1] [volume of a cylindrical paint can 2]=2*[1 gallon]-----> 2 gallons
the answer is the capacity of the lager one is 2 gallons
