since this is a right triangle, you can use the pythagorean theorem:
(a^2+b^2=c^2)
your formula will be:
[tex] {6}^{2} + {b}^{2} = {8}^{2} [/tex]
your hypotenuse will take the place of c. (8) and 6 will take the place of a.
simplify the squares:
[tex]36 + {b}^{2} = 64[/tex]
subtract 36 from each side:
[tex] {b}^{2} = 28[/tex]
un-square the b by square rooting 28.
this will come out as a large # that's equal to:
[tex]2 \sqrt{7} [/tex]
