Respuesta :

carlosego
For this case we have the following relationship:
 P1V1 = P2V2
 Clearing volume 2 we have:
 V2 = (P1 / P2) * (V1)
 Substituting values we have:
 V2 = (5.1 / 1.0) * (350)
 V2 = 1785 mL
 Answer:
 this gas would occupy 1785 mL at 1.0atm