If two chords intersect in a circle, then the products of the measures of the segments of the chords are equal.
I'm assuming that number up top is an 8. It's kind of blurry.
Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
[tex]24 = 10x - x^{2} [/tex]
[tex] x^{2} - 10x + 24 = 0[/tex]
(x - 6)(x - 4) = 0
x - 6 = 0 .... x - 4 = 0
x = 6 .... x = 4
4 or 6
