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How much heat is absorbed by a 28g iron skillet when its temperature rises from 7oC to 29oC?

Respuesta :

Erudite1
From the information given above, 
Mass [M] = 28 g
Change in temperature = 29 - 7 = 22 
Specific heat of iron = 0.449 [This value is constant]
The formula for calculating heat absorbed, Q is
Q = Mass * Specific heat of Iron * change in temperature
Q = 28 * 0.449 * 22 = 276.58 J

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