Answer:
Step-by-step explanation:
1.
[tex](c+9)^2=64=8^2\\[/tex]
c+9=±8
either c=8-9=-1
c=-8-9=-17
so c=-1,-17
D
2.
8x^2-3=2
8x^2=5
[tex]x^2=\frac{5}{8}=\frac{10}{16}[/tex]
[tex]x=±\frac{\sqrt{10}}{4}[/tex]
so A
3.
[tex]x^2+4x+4=18\\(x+2)^2=9*2\\x+2=3\sqrt{2} \\x=-2 ±3\sqrt{2}[/tex]
so D
or
