[tex] \dfrac{3}{4}x-\dfrac{1}{3}x+5=\dfrac{5}{6}x\ \ \ \ \ |\cdot12\\\\12\cdot\dfrac{3}{4}x-12\cdot\dfrac{1}{3}x+12\cdot5=12\cdot\dfrac{5}{6}x\\\\3\cdot3x-4\cdot x+60=2\cdot5x\\\\9x-4x+60=10x\\\\5x+60=10x\ \ \ \ |-60\\\\5x=10x-60\ \ \ \ |-10x\\\\-5x=-60\ \ \ \ |:(-5)\\\\x=12 [/tex]
