roar5 roar5
  • 14-02-2018
  • Mathematics
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Show work and solve asap

Show work and solve asap class=

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mathmate
mathmate mathmate
  • 14-02-2018
Assuming the small squares represent 0.5 unit, then there are zeroes at 
x=-1, x=0 and x=2.
So the polynomial takes the form
y=a(x-(-1)(x-0)(x-2)
or
y=ax(x+1)(x-2)

Since the graph increases indefinitely as x-> + ∞, a is positive, therefore

y=ax(x+1)(x-2)  where a>0
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