The slope of a line that is perpendicular to this line is [tex]-\frac{3}{2}[/tex].
To find the slope of the given line we write it in y=mx+b form.
[tex]2x - 3y - 5 = 0\\3y=2x-5\\y=\frac{2}{3}x-\frac{5}{3}[/tex]
Hence the slope of the given line = [tex]\frac{2}{3}[/tex].
The slope of the perpendicular line will be negative reciprocal. So the slope is = [tex]-\frac{3}{2}[/tex].
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