Answer:
The value of the expression is 2
Step-by-step explanation:
The given expression is [tex]8x^2y^{-2}[/tex]
Substitute x = –1 and y = 2 in this expression
[tex]8(-1)^2(2)^{-2}[/tex]
Now, we know the exponent rule [tex]x^{-a}=\frac{1}{x^a}[/tex]
[tex]8(-1)^2\cdot\frac{1}{2^2}[/tex]
Now, on simplifying, we get
[tex]8\cdot(1)\cdot\frac{1}{4}\\\\=8\cdot\frac{1}{4}\\\\=2[/tex]
The value of the expression for the given values of x and y is 2
