AssuntaGoering608 AssuntaGoering608
  • 15-07-2014
  • Mathematics
contestada

13. Find the exact value of sin 30 ° - sin 45 ° cos 45 ° .
a. 0
b. 1/2
c. 1
d. 2

Respuesta :

Аноним Аноним
  • 15-07-2014
[tex]sin30^o-sin45^ocos45^o\\\\sin30^o=\frac{1}{2}\\\\sin45^o=cos45^o=\frac{\sqrt2}{2}\\\\sin30^o-sin45^ocos45^o=\frac{1}{2}-\frac{\sqrt2}{2}\cdot\frac{\sqrt2}{2}=\frac{1}{2}-\frac{2}{4}=\frac{1}{2}-\frac{1}{2}=0\\\\Answer:a.[/tex]
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vaibhavay
vaibhavay vaibhavay
  • 15-07-2014
sin30  1/2
sin45*cos45=1/2
=>  1/2  -  1/2 = 0
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