dalonicole
dalonicole dalonicole
  • 15-01-2018
  • Mathematics
contestada

Given a regular square pyramid with RS = 6 and PX = 4, find the following measure. XT =

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MrsMeseeks
MrsMeseeks MrsMeseeks
  • 17-01-2018
I think its 3 sqrt of 2
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calculista
calculista calculista
  • 18-12-2018

Answer:

[tex]XT=3\sqrt{2}\ units[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

Applying the Pythagoras Theorem

[tex]XT^{2}= XY^{2}+YT^{2}[/tex]

In this problem we have

[tex]XY=RS/2=6/2=3\ units[/tex]

[tex]YT=XY=3\ units[/tex]

substitute

[tex]XT^{2}= 3^{2}+3^{2}[/tex]

[tex]XT^{2}= 18[/tex]

[tex]XT=\sqrt{18}\ units[/tex]

Simplify

[tex]XT=3\sqrt{2}\ units[/tex]

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