natalie88 natalie88
  • 15-09-2017
  • Mathematics
contestada

find 4 consecutive odd numbers such that the sum of the first and the forth is 27 less than three times the first

Respuesta :

caylus
caylus caylus
  • 15-09-2017
Hello,

Let's assume

2n-3 the first number
2n-1 the second
2n+1 the third
2n+3 the forth

2n-3+2n+3=3*(2n-3)-27
4n=6n-9-27
2n=36

==>2n-3=33
2n-1=35
2n+1=37
2n+3=39

Proof: 33+39=72
3*33-27=72



Answer Link

Otras preguntas

Without the rise of Islam and the Crusades, the Renaissance might not have taken place. True False
Correct any errors in capitalization or punctuation. Your answer should be a single sentence.Daniel struggled to follow his clients' directive to, "retain the o
Arrange the steps in order to describe what happens to a gas when it cools. In a video game, a flying coconut moves at a constant velocity of 20 meters/second i
what is lim x → -1 ln x​
Why is Claire (the dog) not gaining weight, even though she is eating?
Please help!!!!!!!!!
An electric bulb is marked 250w 230vHow many joule energy does it consume in 1 hour​
if a and b are integers, what conditions would make a×b >0?​
What does purchasing insurance for a business reveal about the business owner’s attitude toward financial risk?
When making bread from scratch, the recipe calls for 3/4 cup of water. If you need to make a smaller portion of the recipe, how much water would you need in or