Answer:
[tex]\text{the value of a is }a=\frac{K}{4+9b}[/tex]
Step-by-step explanation:
Given the equation
[tex]K=4a+9ab[/tex]
we have to solve the above equation for a.
[tex]K=4a+9ab[/tex]
Taking a common from RHS, we get
[tex]K=a(4+9b)[/tex]
Now, divide the equation throughout by 4+9b, we get
[tex]a=\frac{K}{4+9b}[/tex]
which is required value of a.
