Answer: cos(π)+i sin(π)
Step-by-step explanation: e is the Euler's number (2.71828)
i is the imaginary √-1
pi is 3.14159
cos(π) is -1
sin(π) is 0
so e iπ =cos(π)+isin(π)=−1+i⋅0=−1
Answer: cos pi + isin pi
Step-by-step explanation: e is 2.71828
i is sq root of -1
pi is 3.141592654
cos pi + isin pi would be -1
