Seudónimo Seudónimo
  • 15-08-2017
  • Mathematics
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NEED HELP PLEASE don't know how to solve

NEED HELP PLEASE dont know how to solve class=

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Banabanana
Banabanana Banabanana
  • 15-08-2017
The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the intercepted arcs.

[tex] \frac{10x+20-80}{2}=2x+15 \\ 10x-60=2(2x+15) \\ 10x-60= 4x+30 \\ 10x-4x=30+60 \\ 6x=90 \\ x=90/6 \\ x=15[/tex]
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