Breiter Breiter

14-08-2017
Mathematics

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E bisects DF , DE = 5y, and EF = 13y-8. Find DE, EF, and DF

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apologiabiology apologiabiology

14-08-2017

it bisects so DE=EF

DE=5y
EF=13y-8

so
5y=13y-8
minus 13y both sides
-8y=-8
divide both sides by -8
y=1

DE=5y=5(1)=5

DE=EF=5

DF=DE+EF=5+5=10

DE=5
EF=5
DF=10

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