freemantatyanna freemantatyanna

12-08-2017
Physics

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Please help.

How much heat is needed to raise the temperature of 53g of water by 89oC? Joules

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13-08-2017

[tex]Given:\\\\m=53g=0.053kg\\\\c=4200 \frac{J}{kg\cdot ^\circ C} \\\\\Delta t=89^\circ C\\\\Find:\\Q=?\\\\Solution:\\\\Q=cm\Delta t\\\\Q=4200 \frac{J}{kg\cdot ^\circ C}\cdot 0.053kg\cdot 89^\circ C=19811,4J[/tex]

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