SlightDrizzle2
SlightDrizzle2 SlightDrizzle2
  • 16-01-2024
  • Mathematics
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Please show work!!!!!!!!!!!!!!!!

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Adithya027
Adithya027 Adithya027
  • 16-01-2024

Step-by-step explanation:

Using Pythagoras Theorem,

[tex]BA=\sqrt{6^2-3^2}[/tex]

[tex]BA=\sqrt{36-9}[/tex]

[tex]BA=\sqrt{27}[/tex]

[tex]BA=3\sqrt{3}[/tex]

[tex]x=BA-3[/tex]

[tex]x=3\sqrt{3}-3[/tex]

∴[tex]x=3(\sqrt{3}-1)[/tex]

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