15-01-2024
Mathematics

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(3x-2)(x+4)-3(x+5)(x-1)=0 find the root

Respuesta :

Marver1ck Marver1ck

15-01-2024

Answer:

x = [tex]\frac{7}{2}[/tex]

Step-by-step explanation:

(3x-2)(x+4)-3(x+5)(x-1) = 0

3x² + 10x - 8 - 3x² - 12x + 15 = 0

-2x + 7 = 0

-2x = -7

x = [tex]\frac{7}{2}[/tex]

So, the answer is x = [tex]\frac{7}{2}[/tex].

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