Respuesta :

irspow
Unique pair of dates...use "n choose k" formula:

n!/(k!(n-k)!), n=number of total possible choices, k=number of selections

365!/(2!(363!))

66430 unique combinations
mreijepatmat
The first date has 365 possible outcome
The second date has 364 possible outcome (since one day already selected)
The total outcome is 365 x 364 =132,860 outcomes

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