How many aluminum atoms are in 3.28 g of al2s3?

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11-06-2017
Chemistry

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How many aluminum atoms are in 3.28 g of al2s3?

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LeChatNoir LeChatNoir · Answer 1 · 2017-06-11T11:29:08+02:00

LeChatNoir LeChatNoir

11-06-2017

m Al₂S₃: 27g×2 + 32g×3 = 150 g/mol

150 g/mol Al₂S₃ ==>> 2 moles of Al ==>> 12,04·10²³ atoms of Al
--------------------------------------
150g ------- 12,04·10²³ Al
3,28g ------ X
X = (3,28×12,04·10²³)/150g
X = 0,2633·10²³ = 2,633·10²² aluminium atoms

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