Respuesta :

irspow
The vertex of a quadratic occurs when the velocity, dy/dx=0.

dy/dx=2x+8, so dy/dx=0 only when:

2x+8=0

2x=-8

x=-4, now you find the y coordinate which is:

y(-4)=(-4)^2+8(-4)+12

y(-4)=16-32+12

y(-4)=-4 so the vertex is at the point:

(-4,-4)
mjankiewicz
[tex]y=x^2+8x+12\\\\ y=(x-p)^2+q \\\\ [/tex] W = (p,q)

[tex]y=(x+4)^2-16+12\\\\ y=(x+4)^2-4[/tex]
W = (-4, -4)

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