Respuesta :

konrad509
[tex]-\dfrac{5}{6}+\dfrac{x}{6}=\dfrac{1}{x}|\cdot6x\qquad(x \not=0)\\ -5x+x^2=6\\ x^2-5x-6=0\\ x^2+x-6x-6=0\\ x(x+1)-6(x+1)=0\\ (x-6)(x+1)=0\\ x=6 \vee x=-1 [/tex]
Hippalectryon
[tex]-5/6+x/6=1/x\Leftrightarrow x^2-5x-6=0[/tex]

[tex]\Delta=25+24=7^2[/tex] hence the answer is [tex]\frac{5\pm7}{2}=\left\lbrace-1,6\right\rbrace[/tex]

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