[tex]\bf \begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\
\end{array}
\qquad
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-----------------------------\\\\
so\quad
\begin{cases}
\textit{the equation went from}\\\\
(y-4)^2=-4(x+3)\\\\
to\\\\
(y-4)^2=-4(x+10)
\end{cases}[/tex]
notice the h,k vertex of the first one
notice the second one, notice how "h" changed
