zach553
zach553 zach553
  • 12-03-2017
  • Mathematics
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h= -16t^2+4+18t What is the meaning of 4 in this function

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jdoe0001 jdoe0001
  • 12-03-2017
[tex]\bf \textit{initial velocity}\\ h = -16t^2+v_ot+h_o \qquad \text{in feet}\\ \\ \quad \\ v_o=\textit{initial velocity of the object}\\ h_o=\textit{initial height of the object}\\ h=\textit{height of the object at "t" seconds}\\\\ -----------------------------\\\\ H(t)= -16t^2+4+18t\implies \begin{array}{llll} H(t)= -16t^2+18t&+4\\ &\uparrow \\ &h_o \end{array} [/tex]
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