Data:
copper(II) phosphate
Formula: Cu3(PO4)2
In each mol there are 6,02*10²³ atoms
Cu3 (PO4)2, observing the formula are 2 mol of P (Phosphorus) that is 2 times 6.02 * 10²³, which is equal to 12.04 * 10²³ atoms.
Therefore, in 5.20 mol of copper(II) phosphate?
5.20 * 12.04 * 10²³ ≈ 62.60*10²³atoms or 6,26*10^24 atoms
Answer:
[tex]\boxed{\boxed{\approx62.60*10^{23}atoms}}or\boxed{\boxed{\approx6.2*10^{24}atoms}}[/tex]
