rosamelano19 rosamelano19

14-02-2017
Mathematics

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Perform the indicated operation. (w 3 + 64) ÷ (4 + w)

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Аноним Аноним

14-02-2017

w³ + 64 = w³ + 4³ = (w+4)³ - 3*w*4(w+4) = (w+4)[(w+4)² - 12w]

(w³ + 64) ÷ (w+4)
=(w+4)[(w+4)² - 12w] ÷ (w+4)
= (w+4)² - 12w
= w² -4w + 16

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