pwrlss06 pwrlss06

14-02-2017
Mathematics

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I need 2 cones with different dimensions but the same volume

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wolf1728 wolf1728

14-02-2017

Cone Volume = (π • r² • h) ÷ 3

radius = 4
height = 24
Cone Volume = (PI *4*4*24)/3
Cone Volume = 402.12

If we reduce the height by 4 (from 24 to 6) then we have to increase the radius by 2 (from 4 to 8) because the radius is squared.
Cone Volume = (PI *8*8*6)/3
Cone Volume = 402.12

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