Answer:
297.4332 grams of chlorine is present in 465 grams of calcium chloride.
Explanation:
Mass of calcium chloride = 465 g
Molar mass of calcium chloride = 111 g/mol
Moles of calcium chloride = [tex]\frac{465 g}{111 g/mol}=4.1892 mol[/tex]
1 mol of calcium chloride has 2 moles of chlorine atoms.
Then 4.1892 moles of calcium chloride has:
[tex]2 \times 4.1892 mol=8.3784 mol[/tex] of chlorine atoms
Mass of 8.3784 moles of chlorine atom:
8.3784 mol × 35.5 g/mol=297.4332 g
