19deita
19deita
13-02-2017
Mathematics
contestada
Cotx/cscx-sinx =secx
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LammettHash
LammettHash
13-02-2017
[tex]\dfrac{\cot x}{\csc x-\sin x}=\dfrac{\cot x\sin x}{(\csc x-\sin x)\sin x}=\dfrac{\cos x}{1-\sin^2x}=\dfrac{\cos x}{\cos^2x}=\dfrac1{\cos x}=\sec x[/tex]
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