Answer:
1st and 3rd answers are correct.
Step-by-step explanation:
[tex] \sf2x + 3 \leqslant x - 5[/tex]
First, to take x left side, subtract x from both sides.
[tex] \sf2x + 3 - x \leqslant x - x - 5 \\ \sf \: x + 3 \leqslant - 5[/tex]
To take 3 to the left side, subtract 3 from both sides.
[tex] \sf \: x + 3 - 3 \leqslant 5 - 3 \\ \sf \: x \leqslant 5 - 3 \\ \sf \: x \leqslant 2[/tex]
