Respuesta :

subtomex0

[tex]sum \: of \: interior \: angles = (9 - 2)180 = 1260 \\ one \: angle \: in \: th e\: nonagon = \frac{1260}{9} = 140 \\ x + nop = 180 \: (supplementary \: angles) \\ x + 140 = 180 \\ x = 180 - 140 \\ x = 40[/tex]

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