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In a factory there are two separate containers of stress balls. in the first container are 80 balls, and in the second are 90 balls. 40% of the balls in the first container are defective, and 20% in the second container are defective. in total, how many balls in the two containers are defective?

Respuesta :

Total balls in the two containers that are defective = 50

Given,

The balls in first container = 80

The balls in second container = 90

Defective balls in 1 container = 40% of 80

= 40 / 100 × 80

= 32

Defective balls in 2 container = 20% of 90

= 20 / 100 × 90

= 18

Now, the total numbers defective balls = 32 + 18

= 50

Therefore, there are 50 defective balls in total.

To learn more about percentage from the given link

https://brainly.com/question/24304697

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