Answer: C, (-1, -5)
Step-by-step explanation:
A = 2, B = 4, C = -3
We know the graph opens up because a is positive.
This rules out A and D
We are left with B and C as options.
Let's change this into vertex form
[tex]y=a(x-h)^2[/tex]
Complete the square
[tex]2(x+1)^2-5[/tex]
now a = 2, h = 1, k = -5
The vertex is (h, k)
plug in values:
(-1, -5)
