Answer: A
Step-by-step explanation:
Letting [tex]f(y)=x[/tex],
[tex]x=\sqrt{y}-5\\\\x+5=\sqrt{y}\\\\y=(x+5)^{2}[/tex]
Also, the domain of an inverse is the same as the range of the original function, so the range is [tex]x \geq 0[/tex]
