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  • 15-06-2022
  • Mathematics
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−3x(4x² − 81) (x² + 64) = 0

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rdacoder
rdacoder rdacoder
  • 15-06-2022

Answer: [tex]x=0,x=-\frac{9}{2}, x=\frac{9}{2}[/tex]

Step-by-step explanation:

[tex]-3x(4x^2-81)(x^2+64)=0\\[/tex]

multiply the terms together

[tex]-12x^5-525x^3+15552x=0[/tex]

factor left side of the equation

[tex]3x(-x^2-64)(2x+9)(2x-9)=0[/tex]

set factors equal to 0

[tex]x=0,x=-\frac{9}{2}, x=\frac{9}{2}[/tex]

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