mliu77131 mliu77131
  • 12-06-2022
  • Mathematics
contestada

determine a quadratic equation, in standard form, that has the pair of root: x=-3, x=5

Respuesta :

loneguy
loneguy loneguy
  • 12-06-2022

Answer:

[tex]x^2 -2x -15=0[/tex]

Step-by-step explanation:

[tex]\text{Given that, the roots are,}~ \alpha=-3 ~ \text{and}~ \beta=5 .\\\\\text{The quadratic equation with roots}~ \alpha ~ \text{and}~ \beta ~ \text{is,}\\\\~~~~~~~~x^2 - (\alpha + \beta )x +\alpha \beta = 0\\\\\implies x^2-(-3 +5) x +(-3)(5) = 0\\\\\implies x^2 -2x -15=0[/tex]

Answer Link
PrindelaJema
PrindelaJema PrindelaJema
  • 12-06-2022

Answer:

x²-2x-15=0

Step-by-step explanation:

x=-3 x=5

x+3=0 x-5=0

(x+3)(x-5)=0

x²-5x+3x-15=0

x²-2x-15=0

Answer Link

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