[tex]\dfrac 1{x+y} + \dfrac{3}{x-y} + \dfrac{2}{x^2-y^2} \\\\\\=\dfrac 1{x+y} + \dfrac{3}{x-y} + \dfrac{2}{(x+y)(x-y)}\\ \\\\=\dfrac{x-y+3(x+y)+2}{(x+y)(x-y)}\\\\\\=\dfrac{x-y+3x+3y+2}{(x+y)(x-y)}\\\\\\=\dfrac{4x+2y+2}{(x+y)(x-y)}\\\\\\=\dfrac{2(2x+y+1)}{(x+y)(x-y)}[/tex]
