lorenzoharvey08 lorenzoharvey08
  • 11-03-2022
  • Engineering
contestada

7)
Given a series silicon diode circuit with the resistor R=2 ko ohms and an applied voltage of 10
V, what is Ipg?
A) 0.5 mA
B) 10 mA
C) 4.65 mA
D) 1.0 mA

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 12-03-2022

Answer:

  C)  4.65 mA

Explanation:

The series circuit will have a voltage drop of about 0.7 V across the silicon diode, so the voltage drop across the 2 kΩ resistor is 10 -0.7 = 9.3 V. The current through the resistor is given by Ohm's Law:

  I = V/R = 9.3 V/(2 kΩ)

  I = 4.65 mA

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