where,
now
applying tan 30°
tan theta = perpendicular/base
=>tan 30° = 6/a
(since tan 30° = 1/√3)
=>1/√3 = 6/a
=> a = 6√3
applying cos Q for finding b
=>cos 60° = b/h
(since cos 60° = 1/2)
=>1/2= 6/b
=> b= 12
