Answer:
5√(x^1/3-5)
Step-by-step explanation:
hey!
f(x)=(x^5 +5)^1/3
let f(x) be y
y=(x^5 +5)^1/3
now, interchanging x and y
or, x=(y^5 +5)^1/3
or, ∛x= y^5 + 5
or, x^1/3-5=y^5
or, y=5√(x^1/3-5)
therefore f^-1=5√(x^1/3-5)
hope it helps!
thank u!
