Answer:
[tex]x\approx5.8[/tex]
Step-by-step explanation:
[tex]tan\theta=\frac{opposite}{adjacent}[/tex]
[tex]tan30^\circ=\frac{x}{10}[/tex]
[tex]10tan30^\circ=x[/tex]
[tex]10(\frac{\sqrt{3}}{3})=x[/tex]
[tex]\frac{10\sqrt{3}}{3}=x[/tex]
[tex]x\approx5.8[/tex]
