[tex]\large\huge\green{\sf{Answer:-}}[/tex]
[tex] \red {\mathbb{ \underline { \tt By \: ASA\: congruence \: postulate}}}[/tex]
➡in ∆ ORS and ∆OUT
➡ UO = 0S ( given)
➡UOT = SOR ( by vertically opposite angle)
➡OUT= OSR( by alternate angle)
( bcaz UT is parallel to RS
there fore ,
- ∆ ORS ≅ ∆OUT (by ASA congruence postulate)
