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A dramatic classroom demonstration involves cooling a balloon from room temperature (293 K ) to liquid nitrogen temperature (77 K). If the initial volume of the balloon is 2.6 L , what will its volume be after it cools

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raphealnwobi

The volume of the balloon after it cools is 0.68 L.

Charles law states that the volume of a gas is directly proportional to its temperature at constant pressure.

It is given by:

V ∝ T

V/T = constant

Therefore:

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2} \\\\V_1=2.6\ L,T_1=293\ K,T_2=77\ K:\\\\\frac{2.6}{293}=\frac{V_2}{77} \\\\V_2=\frac{2.6}{293}*77\\\\V_2=0.68\ L[/tex]

Hence the volume of the balloon after it cools is 0.68 L.

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